Question

Qual o valor externo de (-b+√b^2-4*a*c/2*a)? (Bhaskara)

Sabendo que (a= 2) , (b= -5*√3) , (c= 6).

Answer 1

$\frac{ - ( - 5 \sqrt{3}) + \sqrt{ ( - 5\sqrt{ 3} ) {}^{2} - 4.2.6 }}{2.2} \\ \\ \frac{ 5 \sqrt{3} + \sqrt{ 75 - 48}}{4} \\ \\ \frac{ 5 \sqrt{3} + \sqrt{ 27}}{4} \\ \\ \frac{ 5 \sqrt{3} +3 \sqrt{3} }{4} \\ \\ \frac{8 \sqrt{3} }{4} = 2 \sqrt{3}$