Question

Converta para a escala Fahrenheit:
A) 368 k

b)313 k

(com as contas pfvv)

Answer 1

A equação de relação de Fahrenheit e Kelvin é:

$T_{f} = \frac{(T_{k}-273). 9 + 32 }{5}$

Logo,

a)

$T_{f} = \frac{(368-273). 9+32}{5}$

$T_{f} = \frac{95.9+32}{5}$

$T_{f} = \frac{855+32}{5}$$T_{f} = \frac{887}{5} = 177,4$

b)

$T_{f} = \frac{(313-273).9 +32}{5}$

$T_{f} = \frac{40.9+32}{5}$$T_{f} = \frac{360 +32}{5} = \frac{392}{5} = 78,4$