Question

Poderiam me ajudar?
$5x {}^{2} - 4x + 16 = 4x + 116$
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Answer 1

$5x^2-4x+16~=~4x+116\\\\\\5x^2-4x-4x+16-116~=~0\\\\\\5x^2-8x-100~=~0\\\\\\Bhaskara\\\\\\\Delta~=~(-8)^2-4.5.(-100)~=~64+2000~=~\boxed{2064}\\\\\\x'~=~\frac{8+\sqrt{2064}}{2~.~5}~=~\frac{8+\sqrt{4~.~4~.129}}{10}~=~\frac{8+4\sqrt{129}}{10}~=~\boxed{\frac{4+2\sqrt{129}}{5}}\\\\x''~=~\frac{8-\sqrt{2064}}{2~.~5}~=~\frac{8-\sqrt{4~.~4~.129}}{10}~=~\frac{8-4\sqrt{129}}{10}~=~\boxed{\frac{4-2\sqrt{129}}{5}}$