Question

$- 6 + 6 \times + 4 - 2 { \times }^{2} = 2$
resolva e ache x1 e x2

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Answer 1

Resposta: {2,1}

-6 +6x + 4 -2x² = 2

-2x² + 6x -6 +4 - 2 = 0

-2x² + 6x - 4 =0

a= -2

b= 6

c= -4

Δ = b² - 4ac

Δ = 6² - 4.(-2).(-4)

Δ = 36 - 32

Δ = 4

x' = (-6 + √4)/2. (-2)∴ x' = (-6 +2)/-4∴ x' = -4/-4∴ x' = 1

x'' = (-6-2)/-4 ∴ x'' = -8/-4 ∴x'' = 2