Respostas
respondido por:
19
{2x[7-8:5]:4}²
{2x[7-1,6]:4}²
{2x5,4:4}²
{2 x 1,35}²
{2,7}² = 729
{2x[7-1,6]:4}²
{2x5,4:4}²
{2 x 1,35}²
{2,7}² = 729
respondido por:
40
.
![\{2\times[7-( \sqrt{16} +1)\div5]\div4\}^2= \\ \\ \{2\times[7-(4+1)\div5]\div4\}^2= \\ \\ \{2\times[7-5\div5]\div4\}^2= \\ \\ \{2\times[7-1]\div4\}^2= \\ \\ \{2\times6\div4\}^2= \\ \\ \{12\div4\}^2= \\ \\ \{3\}^2=\fbox{$9$}](https://tex.z-dn.net/?f=%5C%7B2%5Ctimes%5B7-%28+%5Csqrt%7B16%7D+%2B1%29%5Cdiv5%5D%5Cdiv4%5C%7D%5E2%3D+%5C%5C++%5C%5C+%5C%7B2%5Ctimes%5B7-%284%2B1%29%5Cdiv5%5D%5Cdiv4%5C%7D%5E2%3D+%5C%5C++%5C%5C+%5C%7B2%5Ctimes%5B7-5%5Cdiv5%5D%5Cdiv4%5C%7D%5E2%3D+%5C%5C++%5C%5C+%5C%7B2%5Ctimes%5B7-1%5D%5Cdiv4%5C%7D%5E2%3D+%5C%5C++%5C%5C+%5C%7B2%5Ctimes6%5Cdiv4%5C%7D%5E2%3D+%5C%5C++%5C%5C+%5C%7B12%5Cdiv4%5C%7D%5E2%3D+%5C%5C++%5C%5C+%5C%7B3%5C%7D%5E2%3D%5Cfbox%7B%249%24%7D "\{2\times[7-( \sqrt{16} +1)\div5]\div4\}^2= \\ \\ \{2\times[7-(4+1)\div5]\div4\}^2= \\ \\ \{2\times[7-5\div5]\div4\}^2= \\ \\ \{2\times[7-1]\div4\}^2= \\ \\ \{2\times6\div4\}^2= \\ \\ \{12\div4\}^2= \\ \\ \{3\}^2=\fbox{$9$}")
vitorianavith:
Obrigada mesmo , minha professora nao explicou nada sobre expressão
Valeu ...♥
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