Question

$9x = \sqrt[4]{27}$
me ajudem, tenho teste amanhã e n consigo entender
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Answer 1

$9^x = \sqrt[4]{27}\\ \\(3^2)^x = \sqrt[4]{3^3}\\ \\3^{2x} = 3^\frac{3}{4}\\\\2x = \frac{3}{4}$

$x = \frac{3}{8}$