Question

Determine as coordenadas do vértice f(x)=x²+3

Answer 1

Resposta:

f(x)=x²+3=ax²+bx+c  .....a=1, b=0 e c=3

V=(vx,vy)

vx=-b/2a=0/(-2)=0

vy=-Δ/4a =-[b²-4ac]/4a=-[0²-4*1*3]/4=3

Vértice ==> (0,3)