Question

matemática por favor mim ajuda

Answer 1

f(x) = x^2 - 2x + 2

f(-3) = (-3)^2 - 2(-3) + 2 = 9 + 6 + 2 = 17

f(-1) = (-1)^2 - 2(-1) + 2 = 1 +2 + 2 = 5

f(0) = (0)^2 - 2(0) + 2 = 0 - 0 + 2 = 2

f(2/3) = (2/3)^2 - 2(2/3) + 2 = 4/9 - 4/3 + 2 = 4/9 - 12/9 + 18/9 = 10/9

f(√2) = (√2)^2 - 2√2 + 2 = 2 - 2√2 + 2 = 4 - 2√2 = 2(2 - √2)

Answer 2

$f(x)= x^{2} -2x+2\\\\\\ a)f(-3)\to (-3)^{2} -2*(-3)+2\to 9+6+2\to 17\\\\\\\\b)f(-1)\to (-1)^{2} -2*(-1)+2\to 1+2+2\to 5\\\\\\\\ c)f(0)\to 0^{2} -2*0+2\to 0-0+2\to 2\\\\\\\\ d)f( \frac{2}{3} )\to ( \frac{2}{3})^{2} -2*( \frac{2}{3})+2\to \frac{4}{9}- \frac{4}{3}+2\to mmc=9\to\\ \frac{ 4-12+18}{9}\to  \frac{-12+22}{9} \to  \frac{10}{9}  \\\\\\\\ e)f( \sqrt{2} )\to (\sqrt{2})^{2} -2*\sqrt{2}+2\to (\sqrt{4}) -2\sqrt{2}+2\to 2-2\sqrt{2}+2\to \\4-2\sqrt{2}\to 2(2- \sqrt{2} )$