Question

transforme em fração irredutível cada dízima periódica:
A)3,111...
B)0,121212
C)0,2515151

Answer 1

A)3,111... = 31-3/9 = 28/9

B)0,121212 = 12/99 = 4/33

C)0,2515151=251-2/990 = 249/990 = 83/330

Answer 2

A) 3,111 x10

31,1111

10x=31,1111-3,11111

10x=28

10x-x=9/28

28/9

B) 0,121212 x100

100x=12,121212-0,121212

100x=12

100x-x=99x

x=12/99÷3

4/33

C) 0,251515x10

2,5151515x100

251-2

100x=249

100x-x=99x

x=249/99÷3

x=83/33