Question

resolva a equação 
(2x-3)(x-8)=34

Answer 1

$(2x-3)(x-8)=34 \\ \\ 2x^2-16x-3x+24-34=0 \\ \\ 2x^2-19x-10=0 \\ \\ \Delta=(-19)^2-4.2.(-10)=361+80=441 \\ \\ x=\frac{19+-21}{4} \\ \\ x_1=10 \\ \\ x_2=-\frac{1}{2}$

Answer 2

(2x-3)(x-8)=34
2x^2-16x-3x+24=34
2x^2-19x+24-34=0
2x^2-19x-10=0

Ultilizando Baskara tera que 

-b+ou-(b^2-4.a.c)^1/2  /2

entao tera 19 +ou- (361-4.2.-10) /2.2

entao tera 19+ou- (441)^1/2 /4

X1 = 19+ 21 /4 = 40 /4 X1=10

X2 =19-21 /4 = -2 /4  X2 = -1/2