Question

nas cntp qual o volume ocupado por 60g de co2​

Answer 1

$MM_{CO_{2}} = 44\frac{g}{mol} \\ n_{CO_{2}} = \frac{60g}{44\frac{g}{mol}} = 1,36mol \\  P = 1 atm \\ R = 0,082 atm.L.mol^{-1} \\ T = 273K \\ V = \frac{n_{CO_{2}}*R*T}{P} = \frac{1,36*0,082*273}\\ V=30,44L$