• Matéria: Matemática
  • Autor: vlaviniab
  • Perguntado 7 anos atrás

equação da reta (-1, 4) e (-6, 4)​

Respostas

respondido por: GeBEfte
2

Utilizando o método do determinante, temos:

\left|\begin{array}{ccc}x_A&y_A&1\\x_B&y_B&1\\x&y&1\end{array}\right|~=~0\\\\\\\\\left|\begin{array}{ccc}-1&4&1\\-6&4&1\\x&y&1\end{array}\right|~=~0\\\\\\\\(~(-1).4.1~+~(-6).y.1~+~x.4.1~)~-~(~1.4.x~+~1.y.(-1)~+~1.4.(-6)~)~=~0\\\\\\(~-4~-~6y~+~4x~)~-~(~4x~-~y~-~24~)~=~0\\\\\\-4~-~6y~+~4x~-~4x~+~y~+~24~=~0\\\\\\-5y~+~20~=~0~~~~~~Simplificando~por~(-5)\\\\\\\boxed{y~-~4~=~0}~~\rightarrow~~Equacao~Geral~da~Reta\\\\\\

Isolando~y,~teremos~a~equacao~reduzida:\\\\\\y~-~4~=~0\\\\\\\boxed{y~=~4}~~\rightarrow~~Equacao~Reduzida~da~Reta

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