Question

$4p2 = 2p \\(k - 1)2 = 9$

Answer 1

$4p {}^{2} - 2p = 0 \\ 2p(2p - 1) = 0 \\ p = 0 \\ ou \\ p = \frac{1}{2}$

$(k - 1)2 = 9 \\ 2k - 2 = 9 \\ 2k = 11 \\ k = \frac{11}{2}$