Resolva, aplicando a fórmula de Bhaskara:
x²-7x+12=0
x²+5x+ 4=0
x²-18x+45=0
- x²- x + 30=0
x²-6x+9=0
x²-3x+10=0
5 x²+6x+3=0
7 x²+x+2=0
2 x²+5x-3=0
6 x²+x-1=0
6 x²-13x+6=0
5 x²-11x+2=0
x²-2x+1=0
x²-4x+5=0
4 x²+11x-3=0
x²-4x-5=0
x²+8x+20=0
x²+6x-4=0
9 x²+6x+1=0
5 x²-3x+1=0
- x²+11x-28=0
Respostas
respondido por:
4
1- Δ
Δ= -4.1.12
Δ= 49-48
Δ= 1
x= -b⁺-√Δ/2.a
x=7⁺₋√1/2
x=7 ⁺₋ 1/2
x'= 7+1=8/2
x'= 4
x''= 7-1=6/2
x''= 3
2-
x^2+5x+4=0
Δ=b^2-4ac
Δ=25-16
Δ=9
x=-5⁺₋√9/2.1
x=-5⁺₋3/2
x'=-5+3=-2/2
x'=-1
x''= -5-3/2= -8/2=-4
3-
Δ=18^2-4.1.45
Δ=324-180
Δ=144
x= 18⁺₋√144/2.1
x'= 18+12/2
x'=30/2=15
x''=18-12/2
x''=6/2=3
4-
-x^2-x+30=0 ×(-1)
x^2+x-30=0
Δ=1^2-4.2.(-30)
Δ=1+120
Δ=121
x'= 1+11/2
x'= 12/2=6
x''=1-11/2
x"=-10/2=-5
5-
x^2- 6x+9=0
Δ=6^2-4.1.9
Δ=36-36
Δ=0
x=6+0/2
x=3
6-
Δ=(-3^2)-4.1.10
Δ=31
sem raíz
Δ= -4.1.12
Δ= 49-48
Δ= 1
x= -b⁺-√Δ/2.a
x=7⁺₋√1/2
x=7 ⁺₋ 1/2
x'= 7+1=8/2
x'= 4
x''= 7-1=6/2
x''= 3
2-
x^2+5x+4=0
Δ=b^2-4ac
Δ=25-16
Δ=9
x=-5⁺₋√9/2.1
x=-5⁺₋3/2
x'=-5+3=-2/2
x'=-1
x''= -5-3/2= -8/2=-4
3-
Δ=18^2-4.1.45
Δ=324-180
Δ=144
x= 18⁺₋√144/2.1
x'= 18+12/2
x'=30/2=15
x''=18-12/2
x''=6/2=3
4-
-x^2-x+30=0 ×(-1)
x^2+x-30=0
Δ=1^2-4.2.(-30)
Δ=1+120
Δ=121
x'= 1+11/2
x'= 12/2=6
x''=1-11/2
x"=-10/2=-5
5-
x^2- 6x+9=0
Δ=6^2-4.1.9
Δ=36-36
Δ=0
x=6+0/2
x=3
6-
Δ=(-3^2)-4.1.10
Δ=31
sem raíz
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