Question

x2= x +12 em baskara​

Answer 1

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$x^2=x+12$

$x^2-x-12=0$

onde:

a = 1

b = —1

c = —12

lembrando que:

$\Delta=b^2-4.a.c$

$\Delta=(-1)^2-4.1.(-12)$

$\Delta=1+48$

$\Delta=49$

$\LARGE{x_{1},_{2}=\frac{-b±\sqrt{\Delta}}{2.a}}$

$\LARGE{x_{1}=\frac{1+\sqrt{49}}{2.1}}$

$\LARGE{x_{1}=\frac{1+7}{2}}$

$\LARGE{x_{1}=\frac{8}{2}}$

$\LARGE{x_{1}=4}$$\checkmark$

$\LARGE{x_{2}=\frac{1-\sqrt{49}}{2.1}}$

$\LARGE{x_{2}=\frac{1-7}{2}}$

$\LARGE{x_{2}=\frac{-6}{2}}$

$\LARGE{x_{2}=-3}$$\checkmark$