Question

y²+12y+36 qual é a resposta?

Answer 1

a=1 b=12 c=36
$x= \frac{-12+- \sqrt{12 ^{2} -4.1.36} }{2.1}$
$x= \frac{-12+- \sqrt{144-144} }{2}$
$x= \frac{-12+- \sqrt{0} }{2}$
$x= \frac{-12+0}{2} = \frac{12}{2} =6$
$x= \frac{-12-0}{2}= \frac{12}{2} =6$
$V=6$

Answer 2

y² + 12y + 36 = 0

$\Delta = b^2 - 4 ac$
$\Delta = 12^2 - 4 * 1 * 36$
$\Delta = 144 - 144$
$\Delta = 0$

X = -b ± √∆
x = - ( 12 )² ± √∆
x = 144 ± 0

x' = 12 + 0 = 12 / 2 = 72
x'' = 12 - 0 = 12 / 2 = 72.

Lembre-se: Se meu ∆ for igual a 0, só teremos uma raiz.