Question

podem me ajudar na alternativa A ?​

Answer 1

320/2

160/2

80/2

40/2

20/2

10/2

5/5

1

180/2

90/2

45/3

15/3

5/5

1

20/2

10/2

5/5

1

$\sqrt{320} + \sqrt{20} - \sqrt{180} =$

$\sqrt{ {2}^{6} \times 5 } + \sqrt{ {2}^{2} \times 5 } - \sqrt{ {2}^{2} \times {3}^{2} \times 5 }= \\ {2}^{3} \sqrt{5} + 2 \sqrt{5} - 2 \times 3 \sqrt{5} = \\ 8 \sqrt{5} + 2 \sqrt{5} - 6 \sqrt{5} = \\ 4 \sqrt{5}$