Question

mim ajudem gente urgente e pra manha sedo

Answer 1

Vou te passar as formulas pois acredito que matematica é algo que se aprende fazendo exercicios. b²-4.a.c
-b+-Raiz de delta/2a
:)

Answer 2

a) x^2-x-20=0
delta=b^2-4ac
delta=(-1)^2-4.1.(-20)
delta=1+80
delta=81
x=-b-/+ raiz de delta/2a
x=-(-1)-9/2.1
x=1-9/2
x=-8/2
x=-4
x=-(-1)+9/2.1
x=1+9/2
x=10/2
x=5
b) x^2-3x-4=0
delta=b^2-4ac
delta=(-3)^2-4.1.(-4)
delta=9+16
delta=25
x=-b-/+ raiz de delta/2a
x=-(-3)-5/2.1
x=3-5/2
x=-2/2
x=-1
x=-(-3)+5/2.1
x=3+5/2
x=8/2
x=4
c) x^2-8x+7=0
delta=b^2-4ac
delta=(-8)^2-4.1.7
delta=64-28
delta=36
x=-b-/+ raiz de delta/2a
x=-(-8)-6/2.1
x=8-6/2
x=2/2
x=1
x=-(-8)+6/2.1
x=8+6/2
x=14/2
x=7
d) x^2-5x+6=0
delta=b^2-4ac
delta=(-5)^2-4.1.6
delta=25-24
delta=1
x=-b-/+ raiz de delta/2a
x=-(-5)-1/2.1
x=5-1/2
x=4/2
x=2
x=-(-5)+1/2.1
x=5+1/2
x=6/2
x=3
e) x^2+x-7=5
x^2+x-7-5
x^2+x-12=0
delta=b^2-4ac
delta=1^2-4.1.(-12)
delta=1+48
delta=49
x=-b-/+ raiz de delta/2a
x=-1-7/2.1
x=-8/2
x=-4
x=-1+7/2.1
x=6/2
x=3
f) (x-5)^2=1
x^2-2.x.(-5)+(-5)^2=1
x^2+10x+25=1
x^2+10x+25-1
x^2+10x+24=0
delta=b^2-4ac
delta=10^2-4.1.24
delta=100-96
delta=4
x=-b-/+ raiz de delta/2a
x=-10-2/2.1
x=-12/2
x=-6
x=-10+2/2.1
x=-8/2
x=-4