Question

dada a função quadrática f(x)=x²-x+1,o valor de f(h+1), é:​

Answer 1

f( x ) = x² -x +1

f(h+1)= (h+1)² -(h+1) +1

f(h+1)= h²+2h+1 -h-1 +1

f(h+1)= h² + h + 1