• Matéria: Matemática
  • Autor: bbys69
  • Perguntado 7 anos atrás

Genti me ajuda com isso pff

Anexos:

Respostas

respondido por: Anônimo
1

Explicação passo-a-passo:

a) -2x.2x=-2.2.x.x=-4.x^{1+1}=-4x^{2}

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b) -2x.\frac{1}{3}x^{2}=-2.\frac{1}{3}.x.x^{2}=-\frac{2.1}{3}.x^{1+2}=-\frac{2}{3}x^{3}=-\frac{2x^{3}}{3}

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c) 4a.(-3b).(-7a)=4.(-3).(-7).a.b.a=-12.(-7).a^{1+1}.b=84a^{2}b

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d) (\frac{1}{2}x)^{2}=\frac{1}{2}.\frac{1}{2}.x.x=\frac{1.1}{2.2}.x^{1+1}=\frac{1}{4}x^{2}=\frac{x^{2}}{4}

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e) (2x^{3}y^{2}z)^{3}=2^{3}.(x^{3})^{3}.(y^{2})^{3}.z^{3}=2.2.2.x^{3.3}.y^{2.3}.z^{1.3}=8x^{9}y^{6}z^{3}

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f) (-\frac{2}{5}ab^{2})^{2}=(-\frac{2}{5}).(-\frac{2}{5}).a^{1.2}.(b^{2})^{2}=\frac{-2.(-2)}{5.5}.a^{2}.b^{2.2}=\frac{4}{25}a^{2}b^{4}=\frac{4a^{2}b^{4}}{25}

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