Question

x ao quadrado + 6x -4 = 0

Answer 1

x^2 + 6x - 4 = 0

x = -6x +/- raiz de 6^2 - 4 × 1 × (-4)

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2×1

x = -6 +/- raiz de 36 + 16

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2

x = -6 +/- raiz de 52

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2

x = -6 +/- 2 raiz de 13

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2

x = -6 + 2 raiz de 13

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2

x = - 3 + raiz de 13.

x = -6 - 2 raiz de 13

x = -3 - raiz de 13.

Answer 2

Resposta:

S = {- 3 - √13; - 3 + √13}

Explicação passo-a-passo:

x² + 6x - 4 = 0

a = 1

b = 6

c = (- 4)

∆ = b² - 4ac

∆ = 6² - 4 · 1 · (- 4)

∆ = 36 + 16

∆ = 52

x = - b ± √∆ /2a

x = - 6 ± √52 /2 · 1

x = - 6 ± 2√13 /2

x¹ = - 6 + 2√13 /2 = - 3 + √13

x² = - 6 - 2√13 /2 = - 3 - √13