Question

Questão 16, por favor

Answer 1

Explicação passo-a-passo:

a) $f(1)=\frac{1^{3}-4}{1}$ → $f(1)=\frac{1-4}{1}$ → $f(1)=\frac{-3}{1}$ → $f(1)=-3$

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b) $f(2)=\frac{2^{3}-4}{2}$ → $f(2)=\frac{8-4}{2}$ → $f(2)=\frac{4}{2}$ → $f(2)=2$

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c) $f(-2)=\frac{(-2)^{3}-4}{-2}$ → $f(-2)=\frac{-8-4}{-2}$ → $f(-2)=\frac{-12}{-2}$ → $f(-2)=6$

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d) $f(3)=\frac{3^{3}-4}{3}$ → $f(3)=\frac{27-4}{3}$ → $f(3)=\frac{23}{3}$

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e) $f(\frac{1}{2})=\frac{(\frac{1}{2})^{3}-4}{\frac{1}{2}}$ → $f(\frac{1}{2})=\frac{\frac{1}{8}-4}{\frac{1}{2}}$ → $f(\frac{1}{2})=\frac{-\frac{31}{8}}{\frac{1}{2}}$ → $f(\frac{1}{2})=-\frac{31}{8}.\frac{2}{1}$ → $f(\frac{1}{2})=-\frac{62}{8}$ → $f(\frac{1}{2})=-\frac{31}{4}$