Question

-4x ao quadrado+8-3=0

Answer 1

$- 4 { x }^{2} + 8 - 3 = 0 \\ - 4 {x}^{2} + 5 = 0 \\ - 4 {x}^{2} = - 5 \\ {x}^{2} = \frac{5}{4} \\ {x } = + - \sqrt { \frac{5}{4} } \\ x = + - \frac{ \sqrt{5} }{2} \\ x1 = - \frac{ \sqrt{5} }{4} \: \: x2 = + \frac{ \sqrt{5} }{2}$