• Matéria: Matemática
  • Autor: aaaaaaaaaakkkaaa
  • Perguntado 7 anos atrás

5x^2-3x-2=0

Formula de bhaskara


evilasylum8: delta=b²-4ac
evilasylum8: delta=(-3)²-4.5.(-2)
evilasylum8: delta=9+40
evilasylum8: delta=49
evilasylum8: X1=3+7/10=10/10=1
evilasylum8: X2=3-7/10=-4/10= -0,4

Respostas

respondido por: AdrianSk
1

5x^2-3x-2=0

A = 5              B = -3             C = -2

\frac{-B\sqrt{B^2-4(AC)} }{2A}

\frac{3\sqrt{(-3)^2-4\times(5\times-2)} }{2\times5}

\frac{3\sqrt{9-4\times10} }{10}

\frac{3\\sqrt{49} }{10}

\frac{3\pm\sqrt{49} }{10}

x=\frac{3\pm7}{10}

x = 1 ; - \frac{2}{5}

Perguntas similares