Question

qual e as raizes de -4t = 3t2 + 4/3

Answer 1

-4t = 3t2 + 4/3

3t² + 4t + 4/3        efetuando MMC

9t² + 12t + 4 = 0

fórmula de Bhaskara , sendo que

:

a=9,b=12,c=4.

$\Delta &= b^2-4\cdot a \cdot c\\\\\Delta &= (12)^2- 4\cdot 9\cdot 4 \\\\\Delta &= 144-144\\\Delta &= 0 \\\\x &= \dfrac{-b\pm\sqrt{\Delta}}{2\cdot a} \\\\x &= \dfrac{-12\pm\sqrt{0}}{2\cdot 9} \\\\x &= \dfrac{-12\pm 0}{18} \\\\x_1 &= \dfrac{-12 + 0}{18} = \dfrac{-2}{3}\\\\x_2 &= \dfrac{-12- 0}{18} = \dfrac{-2}{3}$