Question

quem poder me ajudar eu agradeço dms​

Answer 1

$\frac{19}{4x + 1} = \frac{9x + 1}{5x - 1} \\ \\ 19(5x - 1) = (4x + 1)(9x + 1) \\95x - 19 = 36 {x}^{2} + 4x + 9x + 1 \\ 36 {x}^{2} - 95x + 13x + 1 + 19 = 0 \\ 36 {x}^{2} - 82x + 20 = 0 \\ 18 {x}^{2} - 41x + 10 = 0 \\ \\ x = \frac{41 + - \sqrt{1681 - 720} }{36} \\ \\ x = \frac{41 + - 31}{36} \\ \\ x = \frac{41 + 31}{36} = \frac{72}{36} = 2 \\ ou \\ x = \frac{41 - 31}{36} = \frac{10}{36} = \frac{5}{18}$