Question

calcule
1-$\frac{3}{4} + \frac{0.060606...}{0.121212...}$
2-
$0.888... + \frac{1}{2} + \frac{1}{3} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \frac{2}{5} - \: \frac{1}{10}$
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Answer 1

1 - $\frac{3}{4}$ + $\frac{0.06}{0.12}$

2- 0.8 + $\frac{1}{2}$ + $\frac{1}{3}$

$\frac{2}{5}$ - $\frac{1}{10}$

$\frac{1}{1}$ - $\frac{3}{4}$ + 0.5 ou $\frac{5}{10}$

mmc (4,10) =  20

$\frac{20 - 15 + 10}{20}$ = $\frac{15}{20}$, divide por 5 e fica $\frac{3}{4}$.

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$\frac{2}{1}$ - $\frac{8}{10}$ + $\frac{1}{2}$ + $\frac{1}{3}$

mmc: 2, 3, 10 = 30

$\frac{60 - 24 + 15 + 10}{30}$ = $\frac{61}{10}$

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$\frac{2}{5}$ - $\frac{1}{10}$

mmc: 5, 10: 10

$\frac{4 - 1}{10}$ = $\frac{3}{10}$