Question

2x²+10x+12=0 qual é o delta?

Answer 1

2x² + 10x + 12=0

1) Letras:

a = 2

b = 10

c = 12

2) Delta:

Δ = b² - 4.a.c

Δ = 10² - 4.2.12

Δ = 100 - 96

Δ = 4

Resposta: 4

Answer 2

2x² + 10x + 12 = 0

Onde:

a = 2 ; b = 10 e c = 12

Logo:

∆ = b² —4.a.c

∆ = 10²—4.2.12

∆ = 100 — 96

∆ = 4

x1 =( —10+√4)/2.2

x1 = (—10+2)/4

x1 = —8/4

x1 = —2

X2 = ( —10—√4)/2.2

X2 = (—10—2)/4

X2 = (—12)/4

X2 = —3

O delta é 4.