Question

Quais raízes eu encontro aqui:
8x^3 - 2x =0?
Manda passo a passo, faz favor?

Answer 1

$Dada~a~equa\c{c}\~ao~inicial:\\\\\\8x^3-2x=0\\\\\\Fatorando~o~x:\\\\\\x\cdot(8x^2-2) = 0\\\\\\Assim, temos~que:\\\\\\x = 0~ou~ 8x^2-2 = 0\\\\\\Resolvendo~a~segunda~igualdade:\\\\\\8x^2 - 2 = 0\\8x^2 = 2\\x^2 = \frac{2}{8} \\x = \pm\sqrt{\frac{2}{8}} = \pm \sqrt{\frac{1}{4}} = \pm\dfrac{1}{2}}\\\\\\Dessa~maneira, a~solu\c{c}\~ao~ser\'a:\\\\\\\boxed{S = \{-\frac{1}{2}\,,0\,,\frac{1}{2}\}}$