Question

FORMULA DE BHASKARA x²=x+12

Answer 1

Resposta:

x²-x-12=0

∆= b²-4a.c

∆= (-1)² -4(1.-12)

∆= 1+48

∆= 49

x'= -b +√∆/ 2a ---> 1+7/2(1) ----> 8/2 ----> x'=4

x"= -b - √∆/ 2a ---> 1-7/2(1) ----> -6/2 ----> x"=-3