Question

(X-1)2 + (Y-3)2 +3=0

Answer 1

Se eu entendi, temos:

$(x - 1)^{2} + (y - 3)^{2} + 3 = 0 \\ ( {x}^{2} - 2x + 1) + ( {y}^{2} - 6y + 9) + 3 = 0 \\ {x}^{2} + {y}^{2} - 2x - 6y + 13 = 0 \\ ou \\ {x}^{2} + {y}^{2} -2(x +3y) + 13 = 0$