Question

8 x ao quadrado menos 2X - 1 = 0??​

Answer 1

$8x {}^{2} - 2x - 1 = 0 \\ \\ x = \frac{ - ( - 2)± \sqrt{( - 2) {}^{2} - 4(8)( - 1) } }{2 \times (8)} \\ \\ x = \frac{2± \sqrt{4 + 32} }{16} \\ \\ \\ x = \frac{2±6}{16} \\ \\\ \\ \\ x' = \frac{2 + 6}{16} = \frac{8}{16} = \frac{1}{2} \\ \\ \\ x'' = \frac{2 - 6}{16} = \frac{ - 4}{16} = - \frac{1}{4}$