Question

Alguém por favor me ajude a resolver a questão 10 e 11

Answer 1

10)

$\frac{5}{9} d + 300 = d \\ \\ d = 300 + \frac{5}{9} d \\ \\ d - \frac{5}{9} d = 300 \\ \\ \frac{9}{9} d - \frac{5}{9} d = 300 \\ \\ \frac{9 - 5}{9} d = 300 \\ \\ \frac{4}{9} d = 300 \\ \\ 9( \frac{4}{9} d) = 9 \times 300 \\ \\ 4d = 2700 \\ \\ d = \frac{2700}{4} \\ \\ d = 675$

Ana Julia tinha R$675.

11)

a)

$\frac{5}{9} + \frac{2}{5} \\ \\ \frac{25 + 18}{45} = \frac{43}{45}$

b)

$1 - \frac{43}{45} = \frac{45}{45} - \frac{43}{45} = \frac{2}{45}$

c)

$\frac{43}{45} \times 180 = \frac{7740}{45} = 172$

d)

$\frac{2}{45} \times 180 = \frac{360}{45} = 8$