Question

Quais as raizes da equação abaixo X ao quadrado -5x-6=0

Answer 1

Resposta:

$Aplicando~a~f\'{o}rmula~de~Bhaskara~para~x^{2}-5x-6=0~~\\e~comparando~com~(a)x^{2}+(b)x+(c)=0,~temos~a=1{;}~b=-5~e~c=-6\\\\\Delta=(b)^{2}-4(a)(c)=(-5)^{2}-4(1)(-6)=25-(-24)=49\\\\x^{'}=\frac{-(b)-\sqrt{\Delta}}{2(a)}=\frac{-(-5)-\sqrt{49}}{2(1)}=\frac{5-7}{2}=\frac{-2}{2}=-1\\\\x^{''}=\frac{-(b)+\sqrt{\Delta}}{2(a)}=\frac{-(-5)+\sqrt{49}}{2(1)}=\frac{5+7}{2}=\frac{12}{2}=6\\\\S=\{-1,~6\}$

Answer 2

resolução!

${x}^{2} - 5x - 6 = 0$

∆ = (-5)^2 - 4 * 1 * (-6)

∆ = 25 + 24

∆ = 49

∆ =√49

∆ = 7

X ' = 5 + 7 / 2

X ' = 12 / 2

X ' = 6

X " = 5 - 7 / 2

X " = - 2 / 2

X " = - 1

S = { - 1 , 6 }