Question

derive com ln a função
y= lnx^lnx​

Answer 1

Resposta:

y=ln(x)^(ln(x)=ln(x) * ln(x)  

y'=[ln(x)]' * ln(x) + ln(x)*[ln(x)]'

y'=(1/x) *ln(x) +ln(x) * (1/x)  = [2ln(x)]/x =[ln(x²)] /x