Question

Fórmula de baskara 3x² – 2x – 2 = 0 ajudem pf

Answer 1

Resposta: $\frac{1 + 1\sqrt{7} }{3} , \frac{1-1\sqrt{7} }{3}$

3x² - 2x - 2 = 0

a= 3       b= -2    c = -2

Δ = b² - 4ac

Δ = (-2) ² - 4.3.(-2)

Δ = 4 + 24

Δ = 28

x = (-b ⁺/₋ √Δ)/2a

x' = [- (-2) + √28]/2.3 ∴ x' = [2 + 2√7]/6 ∴ x' = $\frac{2 + 2\sqrt{7} }{6}$ ∴ x' = $\frac{1+ 1\sqrt{7} }{3}$

x'' = $\frac{2 - 2\sqrt{7} }{6}$ ∴  x'' = $\frac{1-\sqrt{7} }{3}$

Obs.: x' e x'' são simplificados por 2. Por isso as respostas:

$\frac{1}{3} + \frac{\sqrt{7} }{3} , \frac{1}{3} - \frac{\sqrt{7} }{3}$

Answer 2

Resposta:

3x²-2x-2=0

x'=[2+√(4+24)]/6=(2+2√7)/6=1/3+√7/3

x''=[2-√(4+24)]/6=(2-2√7)/6=1/3-√7/3