Question

LIM QUANDO X TENDE A 5 DE X²- 7X + 10/ X²-9X+20

Answer 1

$\displaystyle\lim_{x \rightarrow 5} \dfrac{ {x}^{2} - 7x + 10 }{ {x}^{2} - 9x + 20 } = \displaystyle\lim_{x\rightarrow 5} \dfrac{ (x - 2)(x - 5)}{(x - 5)(x - 4)} \\ = \displaystyle\lim_{x\rightarrow 5} \dfrac{ x - 2}{x - 4} = \dfrac{ 5 - 2}{5 - 4} = \dfrac{ 3}{1} = 3$