Question

$2 \sqrt{3} + 3 \sqrt{27} - 6 \sqrt{1 \div 3}$
simplifique o resultado (coloque passo a passo) obrigado​

Answer 1

$2\sqrt{3}~+~3\sqrt{27}~-~6\sqrt{\frac{1}{3}}\\\\\\2\sqrt{3}~+~3\sqrt{3^2~.~3}~-~6\,.\,\frac{1}{\sqrt{3}}\\\\\\2\sqrt{3}~+~3~.~3\sqrt{3}~-~6\,.\,\frac{1}{\sqrt{3}}.\frac{\sqrt{3}}{\sqrt{3}}\\\\\\2\sqrt{3}~+~9\sqrt{3}~-~6\,.\,\frac{1\,.\,\sqrt{3}}{\sqrt{3}^{\,2}}\\\\\\2\sqrt{3}~+~9\sqrt{3}~-~6\,.\,\frac{\sqrt{3}}{3}\\\\\\2\sqrt{3}~+~9\sqrt{3}~-~2\,.\,\frac{\sqrt{3}}{1}\\\\\\2\sqrt{3}~+~9\sqrt{3}~-~2\sqrt{3}\\\\\\\boxed{9\sqrt{3}}$