• Matéria: Matemática
  • Autor: denise3320
  • Perguntado 7 anos atrás

me ajuda a fazer Pfv​

Anexos:

Respostas

respondido por: Anônimo
0

Explicação passo-a-passo:

1- x = B - 2A

  x=\left[\begin{array}{ccc}4&-2&0\\-3&1&-1\\\end{array}\right]-2.\left[\begin{array}{ccc}3&2&-1\\0&-5&4\\\end{array}\right]

  x=\left[\begin{array}{ccc}4&-2&0\\-3&1&-1\\\end{array}\right]-\left[\begin{array}{ccc}2.3&2.2&2.(-1)\\2.0&2.(-5)&2.4\\\end{array}\right]

  x=\left[\begin{array}{ccc}4&-2&0\\-3&1&-1\\\end{array}\right]-\left[\begin{array}{ccc}6&4&-2\\0&-10&8\\\end{array}\right]

  x=\left[\begin{array}{ccc}4-6&-2-4&0-(-2)\\-3-0&1-(-10)&-1-8\\\end{array}\right]

  x=\left[\begin{array}{ccc}-2&-6&2\\-3&11&-9\\\end{array}\right]

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2- x = 2A + B

   x=2.\left[\begin{array}{ccc}3&2&-1\\0&-5&4\\\end{array}\right]+\left[\begin{array}{ccc}4&-2&0\\-3&1&-1\\\end{array}\right]

   x=\left[\begin{array}{ccc}2.3&2.2&2.(-1)\\2.0&2.(-5)&2.4\\\end{array}\right]+\left[\begin{array}{ccc}4&-2&0\\-3&1&-1\\\end{array}\right]

   x=\left[\begin{array}{ccc}6&4&-2\\0&-10&8\\\end{array}\right]+\left[\begin{array}{ccc}4&-2&0\\-3&1&-1\\\end{array}\right]

   x=\left[\begin{array}{ccc}6+4&4+(-2)&-2+0\\0+(-3)&-10+1&8+(-1)\\\end{array}\right]

   x=\left[\begin{array}{ccc}10&2&-2\\-3&-9&7\\\end{array}\right]

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