Question

calcule os valores das coeficientes :a,b,c das equações
1 : 7x-3=2x-4x²
2: (x+2)(x-2)=7×​

Answer 1

1. 7x—3=2x—4x²

4x²+7x—2x=3

4x²+5x—3=0

Onde:

a=4 ; b = 5 e c = —3

∆ = b² —4 * a * c

∆ = 5² —4 * 4 * (—4)

∆ = 25+ 64

∆ = 89

x1,2 = (—b±√∆)/2*a

x1,2=(—5±√89)/2*4

x1,2=(—5±√89)/8

B)

(x+2)(x—2)=7x

x²—2x+2x—4=7x

x²—4=7x

x²—7x—4=0

a = 1 ; b = —7 e c = —4

∆ = b² —4 * a * c

∆ = (—7)²—4*1(—4)

∆ = 49+16

∆ = 65

x1,2 = (—b±√∆)/2*a

x1,2 = (7±√65)/2*1

x1,2 = (7±√65)/2

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