Question

s.o.s

produto de matrizes​

Answer 1

Explicação passo-a-passo:

a) A + B + C

   $\left[\begin{array}{ccc}12&1\\9&5\\\end{array}\right]+\left[\begin{array}{ccc}8&11\\3&6\\\end{array}\right]+\left[\begin{array}{ccc}2&4\\10&7\\\end{array}\right]$

   $\left[\begin{array}{ccc}12+8&1+11\\9+3&5+6\\\end{array}\right]+\left[\begin{array}{ccc}2&4\\10&7\\\end{array}\right]$

   $\left[\begin{array}{ccc}20&12\\12&11\\\end{array}\right]+\left[\begin{array}{ccc}2&4\\10&7\\\end{array}\right]$

   $\left[\begin{array}{ccc}20+2&12+4\\12+10&11+7\\\end{array}\right]=\left[\begin{array}{ccc}22&16\\22&18\\\end{array}\right]$

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b) A - B + C

   $\left[\begin{array}{ccc}12&1\\9&5\\\end{array}\right]-\left[\begin{array}{ccc}8&11\\3&6\\\end{array}\right]+\left[\begin{array}{ccc}2&4\\10&7\\\end{array}\right]$

   $\left[\begin{array}{ccc}12-8&1-11\\9-3&5-6\\\end{array}\right]+\left[\begin{array}{ccc}2&4\\10&7\\\end{array}\right]$

   $\left[\begin{array}{ccc}4&-10\\6&-1\\\end{array}\right]+\left[\begin{array}{ccc}2&4\\10&7\\\end{array}\right]$

   $\left[\begin{array}{ccc}4+2&-10+4\\6+10&-1+7\\\end{array}\right]=\left[\begin{array}{ccc}6&-6\\16&6\\\end{array}\right]$

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c) A - (B + C)

   $\left[\begin{array}{ccc}12&1\\9&5\\\end{array}\right]-(\left[\begin{array}{ccc}8&11\\3&6\\\end{array}\right]+\left[\begin{array}{ccc}2&4\\10&7\\\end{array}\right])$

   $\left[\begin{array}{ccc}12&1\\9&5\\\end{array}\right]-(\left[\begin{array}{ccc}8+2&11+4\\3+10&6+7\\\end{array}\right])$

   $\left[\begin{array}{ccc}12&1\\9&5\\\end{array}\right]-\left[\begin{array}{ccc}10&15\\13&13\\\end{array}\right]$

   $\left[\begin{array}{ccc}12-10&1-15\\9-13&5-13\\\end{array}\right]=\left[\begin{array}{ccc}2&-14\\-4&-8\\\end{array}\right]$

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d) B - C + A

   $\left[\begin{array}{ccc}8&11\\3&6\\\end{array}\right]-\left[\begin{array}{ccc}2&4\\10&7\\\end{array}\right]+\left[\begin{array}{ccc}12&1\\9&5\\\end{array}\right]$

   $\left[\begin{array}{ccc}8-2&11-4\\3-10&6-7\\\end{array}\right]+\left[\begin{array}{ccc}12&1\\9&5\\\end{array}\right]$

   $\left[\begin{array}{ccc}6&7\\-7&-1\\\end{array}\right]+\left[\begin{array}{ccc}12&1\\9&5\\\end{array}\right]$

   $\left[\begin{array}{ccc}6+12&7+1\\-7+9&-1+5\\\end{array}\right]=\left[\begin{array}{ccc}18&8\\2&4\\\end{array}\right]$