Question

Quantos termos tem a P.G. (1/8,1/4,...,64)

Answer 1

Resposta:

P.G. (1/8,1/4,...,64)

a1=1/8

q=a2/a1 =(1/4)/(1/8) =(1/4)*(8/1) =2

an=a1*q^(n-1)

64=(1/8)*2^(n-1)

64*8 =2^(n-1)

2⁶ * 2³ =2^(n-1)

2⁶⁺³=2^(n-1)

2⁹=2^(n-1)

9=n-1

n=10 termos