Question

Me ajudem.Por Favor​

Answer 1

$x = \frac{k}{2} \\ y = \frac{k}{4} \\ 2y = \frac{k}{2}$

$x + 2y = 3(y -1) \\ \frac{k}{2} + \frac{k}{2} = \frac{3k}{4} - 3 \\ \frac{2k + 2k = 3k - 12}{4}$

$4k - 3k = - 12 \\ k = - 12$

$x = \frac{k}{2} = \frac{ - 12}{2} = - 6 \\ y = \frac{k}{4} = \frac{ - 12}{4 } = - 3$