Question

calcule a distancia entre os pontos E(3,-1) e F(3,5)

Answer 1

DEF = √(3-3)² + (5 + 1)²
DEF = √ 0² + 6²
DEF = √36
DEF = 6 unidades

Answer 2

$E(3,-1);F(3,5)\\\\ D_{E,F}= \sqrt{( x_{B} - x_{A} ) ^{2} +( y_{B} - y_{A} )^{2} } \\\\ \\ D_{E,F}= \sqrt{( 3 - 3) ^{2} +(5- (-1) )^{2} } \\\\ D_{E,F}= \sqrt{( 3 - 3) ^{2} +(5+1)^{2} } \\\\ D_{E,F}= \sqrt{( 0) ^{2} +(6)^{2} } \\\\ D_{E,F}= \sqrt{0 +36 } \\\\ D_{E,F}= \sqrt{36 } \\\\ D_{E,F}= 6$