Question

Cuanro é
$\frac{x}{3} \geqslant \frac{x}{ - 4} + \frac{x}{ - 3} + 1$
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Answer 1

$\frac{x}{3} = \frac{x}{-4} + \frac{x}{-3} + 1 \\ 4x = - 3x + 4x + 12 \\ 4x = - 7x + 12 \\ 4x + 7x = 12 \\ 11x = 12 \\ x = \frac{12}{11} \\ x = 1 \times \frac{1}{11} = 1.09$