Question

$2 {x}^{2} + 4x$
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Answer 1

Delta=b^2-4ac
Delta=4^2-4*2*0
Delta=16-0
Delta=16

(-b+-rdelta )/2a
(-4+-4)/4

X1=(-4+4)/4
X1=0/4=0
X1=0 e x2=-2
X2=(-4-4)/4
X2=-8/4= -2