Question

Como resolver a equação: 9yy-12y+4=0

Answer 1

9y²-12y+4=0
Δ=(-12)²-4.9.4
Δ=144-144
Δ=0
como Δ=0⇒x'=x"=-b/2a
-b/2a=-(-12)/2.9=12/18=2/3

Answer 2

9y² - 12y + 4 = 0

a= 9

b= -12

c = 4

Δ= (b)² - 4ac

Δ=(-12)² -4(9).(4)

Δ= 144 - 144

Δ=0

x = -b +- √Δ

       -------------------

           2a

x= -´(-12) +- √0

       --------------------

          2.9

x = +12 +-0

      ------------------

          18

x1 = 12+ 0                                    x2 = 12 -0

       ---------------                             --------------------

          18                                                 18

x1 = 12                                         x2 = 12

       ------                                             -------

         18                                                   18

x1 = 2                                            x2=  2

       ----                                                ---------

         3                                                     3

S={2/3}