Question

Calcule o limite da função (x^3-8)/(x-2), com x tendendo a 2.

Answer 1

$\lim\limits_{x\to2}\dfrac{x^3-8}{x-2}=\lim\limits_{x\to2}\dfrac{(x^2+2x+4)(x-2)}{x-2}=\lim\limits_{x\to2}(x^2+2x+4)=\\\\\\=(2)^2+2(2)+4=4+4+4=12$