• Matéria: Matemática
  • Autor: adz
  • Perguntado 9 anos atrás

resolver equacoes

5(x+2)-3(x+6)=40

 

2(x-1)+3(x+1)=4(x+2)

Respostas

respondido por: larafurlan
6
5x+10-3x-18=40
2x= 40+18-10
X=48/2
X= 24

2X -2 +3X+3 = 4X+8
2X+3X-4X=8-3+2
x=7
respondido por: Eriivan
4
5(x+2)-3(x+6)=40\\5x+10-3x-18=40\\5x-3x=40-10+18\\2x=48\\x= \frac{48}{2} \\x=24


2(x-1)+3(x+1)=4(x+2)\\2x-2+3x+3=4x+8\\2x+3x-4x=8+2-3\\x=7
Perguntas similares