Question

$3 \sqrt{128} -4 \sqrt{50} +2 ^{3} \sqrt{128}-8 ^{3} \sqrt{2}como se calcula??? R:[tex]4 \sqrt{2}$

Answer 1

$3 \sqrt{128} - 4 \sqrt{50} + 2^3 \sqrt{128} - 8^3 \sqrt{2} = 3.8 \sqrt{2} - 4.5 \sqrt{2} + 8.8 \sqrt{2} - 512 \sqrt{2} = 24 \sqrt{2} - 20 \sqrt{2} + 64 \sqrt{2} - 512 \sqrt{2} = 4 \sqrt{2} - 448 \sqrt{2} = -484\sqrt{2} =$